If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-48x+92=0
a = 4; b = -48; c = +92;
Δ = b2-4ac
Δ = -482-4·4·92
Δ = 832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{832}=\sqrt{64*13}=\sqrt{64}*\sqrt{13}=8\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-8\sqrt{13}}{2*4}=\frac{48-8\sqrt{13}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+8\sqrt{13}}{2*4}=\frac{48+8\sqrt{13}}{8} $
| 5x–200=400 | | g^2+69=-18 | | h+13=−13 | | 10x–12=18 | | f^2=55 | | q^2+38=0 | | -2(3x-4)=-6x-3 | | (5x^2+32)=(7x^2) | | k^2–10k+9=0 | | 49=-5n=2n | | k2–10k+9=0 | | 3(x-)+2x=22 | | -8x^2+24x-16=0 | | d^2+57=-32 | | 4x10=26 | | 9m+(-3)(m+6)=2(m+1) | | (3/x+4)-(2/x-4)=3x/x2-16 | | y^2-87=0 | | 13(m-1)=-13 | | 10-6b+12=4b-10b | | 4x6+3=17 | | 2x+2=69 | | -1/3(x+18)=21 | | 3(y-3)=4 | | 2x-4=54-3x | | (8x–5x+15)=(x+2) | | (x+7)^4=81 | | 4(1/8+2)=2(x-8)-1/2x | | 8(x-0.35)=7.20 | | -6(2+x)-(2–2x)=8–2(x–3) | | 2x-14/3=1/2(21-3x) | | 9(x+12)=199 |